Statement: Add the 16-bit number in memory locations 4000H and 4001H to the 16-bit number in memory locations 4002H and 4003H. The most significant ei

Program - 5.a: Add two 16-bit numbers - Source Program 1

Sample problem:

(4000H) = 15H

(4001H) = 1CH

(4002H) = B7H

(4003H) = 5AH

Result = 1C15 + 5AB7H = 76CCH

(4004H) = CCH

Source Program 1:

LHLD 4000H : Get first I6-bit number in HL

XCHG : Save first I6-bit number in DE

LHLD 4002H : Get second I6-bit number in HL

MOV A, E : Get lower byte of the first number

ADD L : Add lower byte of the second number

MOV L, A : Store result in L register

MOV A, D : Get higher byte of the first number

ADC H : Add higher byte of the second number with CARRY

MOV H, A : Store result in H register

SHLD 4004H : Store I6-bit result in memory locations 4004H and 4005H.

HLT : Terminate program execution

Program - 5b: Add two 16-bit numbers - Source Program 2

Source program 2:

LHLD 4000H : Get first I6-bit number

XCHG : Save first I6-bit number in DE

LHLD 4002H : Get second I6-bit number in HL

DAD D : Add DE and HL

SHLD 4004H : Store I6-bit result in memory locations 4004H and 4005H.

HLT : Terminate program execution