Write a program to shift an eight bit data four bits right. Assume that data is in register C.

Source program:

MOV A, C

RAR

RAR

RAR

RAR

MOV C, A

HLT

Statement:Write a program to shift a 16 bit data, 1 bit right. Assume that data is in BC register pair.

Source program:

MOV A, B

RAR

MOV B, A

MOV A, C

RAR

MOV C, A

HLT

Two digit BCD number is stored in memory location 4200H. Unpack the BCD number and store the two digits in memory locations 4300H and 4301H such that

Sample problem

(4200H) = 58

Result = (4300H) = 08 and

(4301H) = 05

Source program

LDA 4200H : Get the packed BCD number

ANI FOH : Mask lower nibble

RRC

RRC

RRC

RRC : Adjust higher BCD digit as a lower digit

STA 4301H : Store the partial result

LDA 4200H : .Get the original BCD number

ANI OFH : Mask higher nibble

STA 4201H : Store the result

HLT : Terminate program execution

Pack the two unpacked BCD numbers stored in memory locations 4200H and 4201H and store result in memory location 4300H. Assume the least significant d

Sample problem:

(4200H) = 04

(4201H) = 09

Result = (4300H) = 94

Source program

LDA 4201H : Get the Most significant BCD digit

RLC

RLC

RLC

RLC : Adjust the position of the second digit (09 is changed to 90)

ANI FOH : Make least significant BCD digit zero

MOV C, A : store the partial result

LDA 4200H : Get the lower BCD digit

ADD C : Add lower BCD digit

STA 4300H : Store the result

HLT : Terminate program execution

Find the 2's complement of the number stored at memory location 4200H and store the complemented number at memory location 4300H.

Sample problem:

(4200H) = 55H

Result = (4300H) = AAH + 1 = ABH

Source program:

LDA 4200H : Get the number

CMA : Complement the number

ADI, 01 H : Add one in the number

STA 4300H : Store the result

HLT : Terminate program execution

Find the l's complement of the number stored at memory location 4400H and store the complemented number at memory location 4300H.

Sample problem:

(4400H) = 55H

Result = (4300B) = AAB

Source program:

LDA 4400B : Get the number

CMA : Complement number

STA 4300H : Store the result

HLT : Terminate program execution

Subtract the 16-bit number in memory locations 4002H and 4003H from the 16-bit number in memory locations 4000H and 4001H. The most significant eight

Sample problem

(4000H) = 19H

(400IH) = 6AH

(4004H) = I5H (4003H) = 5CH

Result = 6A19H - 5C15H = OE04H

(4004H) = 04H

(4005H) = OEH

Source program:

LHLD 4000H : Get first 16-bit number in HL

XCHG : Save first 16-bit number in DE

LHLD 4002H : Get second 16-bit number in HL

MOV A, E : Get lower byte of the first number

SUB L : Subtract lower byte of the second number

MOV L, A : Store the result in L register

MOV A, D : Get higher byte of the first number

SBB H : Subtract higher byte of second number with borrow

MOV H, A : Store l6-bit result in memory locations 4004H and 4005H.

SHLD 4004H : Store l6-bit result in memory locations 4004H and 4005H.

HLT : Terminate program execution.

Statement: Add the 16-bit number in memory locations 4000H and 4001H to the 16-bit number in memory locations 4002H and 4003H. The most significant ei

Program - 5.a: Add two 16-bit numbers - Source Program 1

Sample problem:

(4000H) = 15H

(4001H) = 1CH

(4002H) = B7H

(4003H) = 5AH

Result = 1C15 + 5AB7H = 76CCH

(4004H) = CCH

Source Program 1:

LHLD 4000H : Get first I6-bit number in HL

XCHG : Save first I6-bit number in DE

LHLD 4002H : Get second I6-bit number in HL

MOV A, E : Get lower byte of the first number

ADD L : Add lower byte of the second number

MOV L, A : Store result in L register

MOV A, D : Get higher byte of the first number

ADC H : Add higher byte of the second number with CARRY

MOV H, A : Store result in H register

SHLD 4004H : Store I6-bit result in memory locations 4004H and 4005H.

HLT : Terminate program execution

Program - 5b: Add two 16-bit numbers - Source Program 2

Source program 2:

LHLD 4000H : Get first I6-bit number

XCHG : Save first I6-bit number in DE

LHLD 4002H : Get second I6-bit number in HL

DAD D : Add DE and HL

SHLD 4004H : Store I6-bit result in memory locations 4004H and 4005H.

HLT : Terminate program execution